x^2+2+x+2+x+4=360

Solution for x^2+2+x+2+x+4=360 equation:

x^2+2+x+2+x+4=360

We move all terms to the left:

x^2+2+x+2+x+4-(360)=0

We add all the numbers together, and all the variables

x^2+2x-352=0

a = 1; b = 2; c = -352;
Δ = b2-4ac
Δ = 22-4·1·(-352)
Δ = 1412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1412}=\sqrt{4*353}=\sqrt{4}*\sqrt{353}=2\sqrt{353}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{353}}{2*1}=\frac{-2-2\sqrt{353}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{353}}{2*1}=\frac{-2+2\sqrt{353}}{2}
$